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The density of oxygen 1.43 gm/liter at 0 0Cand pressure 1.0 atm. If a 20 liter cylinder is filled with
oxygen at pressure of 25 atm and temperature 27 0C, what is the mass of oxygen in the cylinder?

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To find the mass of oxygen in the cylinder, we first need to calculate the new density of oxygen at the given conditions of 25 atm and 27°C using the ideal gas law.

Calculate the new density of oxygen at 25 atm and 27°C:

Given:
Initial density of oxygen at 0°C and 1 atm = 1.43 g/l
Initial temperature = 0°C = 273 K
Initial pressure = 1 atm
Volume = 20 liters
Using the ideal gas law formula: P1V1/T1 = P2V2/T2
(1 atm)(20 L)/(273 K) = (25 atm)(20 L)/(300 K)
20/273 = 500/300
0.0733 = 1.6667
Density at 25 atm and 27°C = 1.43 g/L x 0.0733/1.6667 = 0.0626 g/L

Calculate the mass of oxygen in the cylinder:

Mass = Density x Volume
Mass = 0.0626 g/l x 20 L
Mass = 1.252 grams
Therefore, the mass of oxygen in the cylinder is 1.252 grams.
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